Answer:
3+2i ohm.
Explanation:
Here we have a complex number operation. According to Ohm's law V=I*R, so:
[tex]R=\frac{V}{I}\\\\R=\frac{21+i}{5-3i}[/tex]
we need to remove the complex number on the denominator, so we have to multiply by its complement on both side
[tex]R=\frac{21+i}{5-3i}*\frac{5+3i}{5+3i}[/tex]
that gives us:
[tex]R=\frac{102+68i}{34}=3+2i[/tex]