Answer:
The diameter of the hole is 20.04 ± 0.01 cm
The diameter of the piston is 19.92 ± 0.04 cm.
We are given that The clearance is one-half the difference between the diameters.
So, Clearance = [tex]\frac{1}{2}(20.04-19.92)[/tex]
= [tex]0.06[/tex]
Uncertainty in the estimate = [tex]\frac{1}{2}(0.01+0.04)[/tex]
= [tex]0.025[/tex]
So, Clearance with uncertainty is [tex]0.06\pm 0.025[/tex]
Hence the clearance is 0.06 and the uncertainty in the estimate. is 0.025
