Answer:
20 groups
Step-by-step explanation:
The number of different groups possible to choose from would be the combination because order doesn't matter.
Ways of choosing r things from n total things in combination is given by:
[tex]nCr = \frac{n!}{(n-r)!*r!}[/tex]
Where
n ! = n * (n-1) * (n-2) * ....
So here we use
n = 6
r = 3
substituting in formula we get:
[tex]nCr = \frac{n!}{(n-r)!*r!}\\6C3 = \frac{6!}{(6-3)!*3!}\\6C3=\frac{6*5*4*3!}{3!*3*2*1}\\6C3=5*4=20[/tex]
So, 20 groups are possible
