The centers of a 10 kg lead ball and a 60 g lead ball are separated by 15cm. Part A What gravitational force does each exert on the other? Express your answer in newtons.

Respuesta :

Answer:

[tex]1.78\cdot 10^{-9}N[/tex]

Explanation:

The magnitude of the gravitational force between two objects is given by

[tex]F=G\frac{m_1 m_2}{r^2}[/tex]

where

[tex]G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2}[/tex] is the gravitational constant

m1, m2 are the masses of the two objects

r is the separation between them

For the balls in this problem,

[tex]m_1 = 10 kg\\m_2 = 60 g = 0.06 kg\\r = 15 cm = 0.15 m[/tex]

Substituting into the equation, we find the gravitational force that each ball exerts on the other:

[tex]F=(6.67\cdot 10^{-11})\frac{(10)(0.06)}{(0.15)^2}=1.78\cdot 10^{-9}N[/tex]