Respuesta :
Answer
given,
diameter of the circle = 120 m
time =4 min = 4 × 60 = 240 s
linear velocity be = 15 m/s
we know
v = r ω
ω =[tex]\dfrac{v}{r}[/tex]
ω =[tex]\dfrac{15}{60}[/tex]
ω = 0.25 rad/s
angular distance in time 4 min
d = ω t
d = 0.25 × 240
d = 60 radian
b) linear distance
d = s × t
d = 15 × 240
d = 3600 m
Answer:
(a) Angular distance is 4v m
(b) Linear distance is 240 v m
Solution:
As per the question:
Let the uniform speed of the car be 'v' m/s
Diameter of the car, D = 120 m
Radius of the car, r = 60 m
Time, t = 4.00 min = 240 s
Now,
(a) The angular speed of the car is given by:
[tex]\omega = \frac{v}{R} = \frac{v}{60}[/tex] rad/s
Now, the angular displacement is given by:
[tex]\theta = \omega\times t[/tex]
[tex]\theta = \frac{v}{60}\times 240 = 4v[/tex] m
(b) The linear distance, d is given by:
d = vt = 240v m
