Answer:
The answer to your question is: 252000
Step-by-step explanation:
To get the change in kinetic energy, only do the operations given considering priority.
1.- Parenthesis
2.- Multiplication
12×350×(122−62)
12 x 350 x (60)
252000
Answer:
The change in kinetic energy is [tex]10500J[/tex]
Step-by-step explanation:
The expression given is wrong. It should be :
[tex](\frac{1}{2}).(350).(122-62)[/tex] (I)
The equation to calculate the kinetic energy [tex](KE)[/tex] is :
[tex]KE=(\frac{1}{2})mv^{2}[/tex]
Where ''m'' is the mass of the object (in this case it will be the mass of the horse).
Where ''v'' is the speed of the object (in this case it will be the speed of the horse).
The kinetic energy is a scalar quantity.
When the unit of ''m'' is kg and the unit of ''v'' is [tex]\frac{m}{s}[/tex] (meters per second), the unit of kinetic energy is Joule (J).
To calculate the change in kinetic energy between two instants of time, for example between 1 and 2, we can obtain the following equation :
Δ[tex]KE_{1,2}[/tex] = [tex]KE_{2}-KE_{1}[/tex]
Δ[tex]KE_{1,2}=(\frac{1}{2})mv_{2}^{2}-(\frac{1}{2})mv_{1}^{2}[/tex]
Δ[tex]KE_{1,2}=(\frac{1}{2})m(v_{2}^{2}-v_{1}^{2})[/tex] (II)
If we compare the expression (I) and (II) we find that the horse mass is [tex]350kg[/tex], [tex]v_{2}^{2}=122\frac{m^{2}}{s^{2}}[/tex] and [tex]v_{1}^{2}=62\frac{m^{2}}{s^{2}}[/tex].
Finally, if we solve (I) :
[tex](\frac{1}{2}).(350)(122-62)=10500J[/tex]
