Answer:
98,98 kg
Explanation:
We first need to calculate the acceleration the blocks needs to reach to the floor in 6 seconds. We can use the formula [tex]h = V_{0} +\frac{1}{2} at^{2}[/tex] where [tex]V_{0}[/tex] is initial velocity, a is acceleration, h is height and t is time. [tex]V_{0}[/tex] is zero since the block initially has zero velocity.
a = 1/2 * a * 6²
a= 0,05 m/s²
Then we will use the Newton’s second law to determine the net force on the system.
Fnet=m.a
Fnet is net force and m is mass. We will use gravitational constant g as 9.81 m/s2 to find weights of the blocks then use them to find net force.
Fnet = 981 – 9,81m
981 – 9,81m = (100 + m)*0,05
976 = 9,86m
m = 98,98 kg
