Answer:
1.94 s
Explanation:
To find the time of flight of the ball, we can just analyze its vertical motion.
The motion of the ball is a free fall motion, which is a uniform accelerated motion. Therefore we can use the suvat equation:
[tex]s=ut+\frac{1}{2}at^2[/tex]
where
s is the vertical displacement
u = 0 is the initial vertical velocity of the ball
t is the time
[tex]a=g[/tex] is the acceleration of gravity
Chosing downward as positive direction,
s = 18.4 m
[tex]g=9.8 m/s^2[/tex]
And solving for t, we find the time during which the ball is in motion:
[tex]t=\sqrt{\frac{2s}{g}}=\sqrt{\frac{2(18.4)}{9.8}}=1.94 s[/tex]
