Answer:
Either y =[tex]\frac{-2}{3}[/tex] or, y =[tex]\frac{1}{3}[/tex]
Step-by-step explanation:
We have to solve the following quadratic equation
45y² + 15y - 10 =0
Now, dividing both sides with 5 we get, 9y² + 3y -2 =0
Hence, to solve the above equation we have to factorize the left-hand part of the equation.
So, 9y² + 3y - 2 =0
⇒ 9y² +6y -3y -2 =0
⇒ (3y +2) (3y -1 ) =0
⇒ Either (3y +2) =0 or (3y -1) =0
⇒ Either y =[tex]\frac{-2}{3}[/tex] or, y =[tex]\frac{1}{3}[/tex] (Answer)
