Answer:
1956.2 ft-lb
Step-by-step explanation:
We are given that force of the wagon
[tex]F=45(cos 15^{\circ}+sin 15^{\circ} J)[/tex]
Displacement of the wagon =45 i
We know that
Work done, W=[tex]F\cdot v[/tex]
Substitute the values then we get
[tex]W=45(cos 15^{\circ}+sin 15^{\circ} J)\cdot 45i[/tex]
[tex]W= 2025 15^{\circ}[/tex]
[tex]W=2025\times 0.966[/tex]
[tex]w=1956.2 ft- lb[/tex]
Hence, Work done on the wagon=1956.2 ft-lb