Answer:
Both will fall at the same speed
Explanation:
Both rocks S and T will reach the ground at the same time this means the velocities they reach at the end of the fall will be equal assuming that their initial velocities are same and are released at the same time. This happens due to the fact that the Earth's gravity causes an acceleration that is equal irrespective of the mass of the object.
m = Mass of object
M = Mass of the Earth = 5.972 × 10²⁴ kg
r = Radius of Earth = 6371000 km
G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²
[tex]F=ma[/tex]
[tex]F=G\frac{Mm}{r^2}[/tex]
[tex]\\\Rightarrow ma=G\frac{Mm}{r^2}\\\Rightarrow a=G\frac{M}{r^2}\\\Rightarrow a=6.67\times 10^{-11}\frac{5.972\times 10^{24}}{(6371\times 10^3+6400)^2}\\\Rightarrow a=9.79395\ m/s^2[/tex]
The acceleration due to gravity on any body will be 9.79395 m/s²
Answer:At same time
Explanation:
Given
Rock s has 20 times the mass of rock T
They are released from the same height
suppose height from which they are released is h with initial velocity =0
[tex]h=ut+\frac{gt^2}{2}[/tex]
[tex]h=\frac{gt^2}{2}[/tex]
[tex]t=\sqrt{\frac{2h}{g}}[/tex]
as we can see from above expression that time is independent of mass therefore they both reach at same time
