contestada

A CD has to rotate under the readout-laser with a constant linear velocity of 1.25 m/s. If the laser is at a position 3.7 cm from the center of the disk, what are the revolutions per minute (rpms) of the disk?

Respuesta :

Answer:N=322.53 rpm

Explanation:

Given

Linear velocity (v)=1.25 m/s

Position from center is 3.7 cm

we know

[tex]v=\omega \times r[/tex]

[tex]1.25\times 100=\omega \times 3.7[/tex]

[tex]\omega =\frac{125}{3.7}=33.78[/tex]

and [tex]\frac{2\pi N}{60}=\omega[/tex]

[tex]N=\frac{\omega \times 60}{2\pi }[/tex]

[tex]N=\frac{33.78\times 60}{2\pi }[/tex]

N=322.53 rpm

Otras preguntas