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Given these​ results, does it seem that the candy company is providing consumers with the amount claimed on the​ label? ▼ because the probability of getting a sample mean of 0.8537 g or greater when 456 candies are selected ▼ is is not exceptionally small.

Respuesta :

scanram

Answer:

Explanation below on given result...

Step-by-step explanation:

Let´s calculate z-score and refer to the normal distribution tables.

Z = (X - μ)/σ      or       Z = (.8543 - .8605)/.0513 = -.1209

 

The Z-score right area translates probability of 0.5478

 

Given this result:

it is basically the same calculation but with a sample standard deviation:

 

    σx = σ/√n = .0513/√(441) = .0024

 

    Z = (.8543 - .8605)/.0024 = -2.5833

 

The Z-score right area translates probability of 0.9951

 

Probability;

Getting a sample is 0.8543 or greater when 441 candies are selected is not exceptionally small.

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