The value of x is x[tex]\geq -0.686[/tex] and x[tex]\leq 2.186[/tex]
Step-by-step explanation:
Factorisation is not possible in this case since the 2 pairs available will not be giving the same outcome as required in factorisation.
This is a quadratic equation
x² + x² – 3x – 3 = 0
2x² - 3x - 3 = 0
Quadratic formula:
[tex]\frac{-b±\sqrt{b^{2} }-4ac }{2a}[/tex]
a=2
b= -3
x= -3
[tex]\frac{-(-3)+\sqrt{-3^{2} }-4(2)(-3) }{2(2)}[/tex]
= [tex]\frac{3+\sqrt{33} }{4}[/tex]
= 2.186
or
[tex]\frac{-(-3)-\sqrt{-3^{2} }-4(2)(-3) }{2(2)}[/tex]
= [tex]\frac{3-\sqrt{33} }{4}[/tex]
= -0.686
Therefore, the value of x is,
x[tex]\geq -0.686[/tex] and x[tex]\leq 2.186[/tex]
Keyword: Factoring, Quadratic
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