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Calculate the percent by mass of a solution containing 0.21 moles of C12H22O11 (gram-molecular mass = 342 g/mole) in 250 g of water.

Respuesta :

nkirotedoreen46

Answer:

28.728%

Explanation:

We are given;

Moles of the solute, C12H22O11 = 0.21 moles

Molar mass of C₁₂H₂₂O₁₁ = 342 g/mol

Mass of the solvent water = 250 g

We need to calculate the percent by mass of a solution

Step 1: Calculate the mass of the solute

Mass = Number of moles × Molar mass

Therefore;

Mass of solute = 0.21 moles × 342 g/mol

                        = 71.82 g

Step 2: Calculate the percent by mass of the solution

% by mass = (Mass of solute ÷ mass of the solution)× 100

                = (71.82 g ÷ 250 g) × 100

                = 28.728%

Therefore, the percent by mass of the solution is 28.728%

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