Answer:
The light bends away from the normal
Explanation:
We can solve the problem by using Snell's law:
[tex]n_1 sin \theta_1 = n_2 sin \theta_2[/tex]
where:
[tex]n_1[/tex] is the index of refraction of the first medium
[tex]n_2[/tex] is the index of refraction of the second medium
[tex]\theta_1[/tex] is the angle of incidence (angle between the incoming ray and the normal to the interface)
[tex]\theta_2[/tex] is the angle of refraction (angle between the outcoming ray and the normal to the interface)
We can rearrange the equation as
[tex]sin \theta_2 = \frac{n_1}{n_2}sin \theta_1[/tex]
In this problem, light travels from an optically denser medium to an optically rarer medium, so
[tex]n_1 > n_2[/tex]
Therefore, the term [tex]\frac{n_1}{n_2}[/tex] is greater than 1, so
[tex]sin \theta_2 > sin \theta_1\\\rightarrow \theta_2 > \theta_1[/tex]
which means that the angle of refraction is greater than the angle of incidence, and so the light will bend away from the normal.
