Answer:
[tex]7\cdot 10^4 m/s[/tex]
Explanation:
We can solve the problem by using the following suvat equation:
[tex]v=u+at[/tex]
where
v is the final velocity
u is the initial velocity
a is the acceleration
t is the time
For the proton in this problem:
[tex]u=2.35\cdot 10^5 m/s[/tex]
[tex]a = -1.10 \cdot 10^{12} m/s^2[/tex]
[tex]t=1.50\cdot 10^{-7}s[/tex]
Substituting into the equation,
[tex]v=(2.35\cdot 10^5)+(-1.10\cdot 10^{12})(1.50\cdot 10^{-7})=7\cdot 10^4 m/s[/tex]
