Answer:h=5.81 m
Explanation:
Given
Mass of block(m)=0.250 kg
Spring Constant [tex]k=4.45\times 10^3 N/m[/tex]
Initial elongation =0.080 m=8 cm
Thus Initial Potential Energy stored =Final Potential Energy stored in Block
[tex]P_i=\frac{kx^2}{2}[/tex]
[tex]P_i=\frac{4.45\times 10^3\times 64\times 10^{-4}}{2}=14.24 J[/tex]
[tex]P_f=mgh=0.25\times 9.8\times h[/tex]
[tex]P_i=P_f[/tex]
[tex]14.24 =0.25\times 9.8\times h[/tex]
[tex]h=\frac{14.24}{0.25\times 9.8}=5.81 m[/tex]
