Answer:
F= 96.61 N
angle (θ) = 52.35°
Explanation:
given,
One Force F₁ = 76.5 N
second force F₂ = 59 N
That means F₃ must equal –(F₁+F₂) so the net sum of the three is zero.
F₁+F₂, since they are orthogonal, is easy.
F₁+F₂ =
= [tex]\sqrt{(76.5^2 + 59^2)}[/tex]
= 96.61 N
[tex]tan \theta = \dfrac{f_y}{f_x}[/tex]
[tex]tan \theta = \dfrac{76.5}{59}[/tex]
[tex]\theta = tan^{-1}(1.30)[/tex]
[tex]\theta = 52.35^0[/tex]
Force is acting of magnitude F= 96.61 N
angle (θ) = 52.35°
