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Two forces, F1 and F2, act at a point. F1 has a magnitude of 8.60 N and is directed at an angle of 55.0 ∘ above the negative x axis in the second quadrant. F2 has a magnitude of 7.00 N and is directed at an angle of 53.2 ∘ below the negative x axis in the third quadrant. What is the x component Fx of the resultant force?

Respuesta :

Answer:9.125 N

Explanation:

Given

Magnitude of Force [tex]F_1=8.60 N[/tex] at  angle of [tex]55^{\circ}[/tex] above negative x axis

Magnitude of  Force [tex]F_2=7 N[/tex] at  angle of [tex]53.2^{\circ}[/tex] below negative x axis

[tex]\theta _1=180^{\circ}-55^{\circ}=125^{\circ}[/tex]

[tex]\theta _2=180^{\circ}+53.2^{\circ}=233.2^{\circ}[/tex]

Thus net force in x direction

[tex]F_x=F_1\cos \theta _1+F_2\cos \theta _2[/tex]

[tex]F_x=8.6\times \cos (125)+7\times \cos (233.2)[/tex]

[tex]F_x=-9.1251 N[/tex] towards negative x axis

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