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A 400 g model rocket is on a cart that is rolling to the right at a speed of 3.5 m/s. The rocket engine, when it is fired, exerts a 8.0 AND vertical thrust on the rocket. Your goal is to have the rocket pass through a small horizontal hoop that is 20 m above the launch point.At what horizontal distance left of the hoop should you launch?

Respuesta :

Manetho

Answer:

13.72 m

Explanation:

m= 400g

v=3.5 m/s

Thrust = 8N

a= F/m

a = (Thrust- weight)/m= (8-0.4*9.8)/0.4 = 10.2 m/s^2

time [tex]t=\sqrt{\frac{2s}{a} }[/tex]

[tex]t=\sqrt{\frac{2\times20}{10.2} }[/tex] = 3.921 secs

therefore horizontal distance = speed×time  = 3.5×3.921 = 13.72 m

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