Answer:
The average force between the ball and bat during contact is 1131N.
Explanation:
The average force can be found employing Newton's second law:
[tex]F = ma[/tex] (1)
Where F is the force, m is the mass and a is the acceleration.
The acceleration can be determined employing the equations for a Uniformly Accelerated Rectilinear Motion:
[tex]v_{f} = v_{i} + at[/tex] (2)
Where [tex]v_{f}[/tex] is the final velocity, [tex]v_{i}[/tex] is the initial velocity and t is the time.
Then, a will be isolated from equation 2:
[tex]a = \frac{v_{f}-v_{i}}{t}[/tex] (3)
Replacing equation (3) in equation (1) it is gotten:
[tex]F = m\frac{v_{f}-v_{i}}{t}[/tex]
[tex]F = (0.145Kg)\frac{(57.0m/s-37.5m/s)}{(2.50x10^{−3}s)}[/tex]
[tex]F = (0.145Kg)\frac{(19.5m/s)}{(2.50x10^{−3}s)}[/tex]
[tex]F = 1131Kg.m/s{2}[/tex]
But [tex]1N = 1Kg.m/s^{2}[/tex], therefore:
[tex]F = 1131N[/tex]
So, the average force between the ball and bat during contact is 1131N.
