Answer:
[tex]9.67\cdot 10^{-3}m/s^2[/tex]
Explanation:
We can solve the problem by using the following suvat equation:
[tex]v^2-u^2=2as[/tex]
where
v is the final velocity
u is the initial velocity
a is the acceleration
s is the displacement
For the car in this problem:
u = 0 (it starts from rest)
[tex]v=50 km/h \cdot \frac{1000}{3600}=13.9 m/s[/tex] is the final velocity
s = 10 km = 10 000 m is the displacement
Solving for a, we find:
[tex]a=\frac{v^2-u^2}{2s}=\frac{13.9^2}{2(10000)}=9.67\cdot 10^{-3}m/s^2[/tex]
