Answer:
0.4375
Step-by-step explanation:
Data provided in the question:
Average time spent per week on playing organized sport, μ = 5.80 hours
Standard deviation of the population, σ = 3.50 hours per week
Total number of students in the sample, n = 64
Now,
The standard error of the sample mean = [tex]\frac{\sigma}{\sqrt{n}}[/tex]
on substituting the respective values, we get
The standard error of the sample mean = [tex]\frac{3.50}{\sqrt{64}}[/tex]
or
The standard error of the sample mean = 0.4375
