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As a 1,330 kg truck travels up a 16.1 m high hill, the nonconservative forces of friction and the force generated by the engine do work on the truck. If the work done by friction is −3.23 105 J and the work done by the engine is +6.57 105 J, determine the change in the truck's kinetic energy (in kJ) as it travels from the bottom of the hill to the top of the hill

Respuesta :

Answer:[tex]5.43\times 10^5 J[/tex]

Explanation:

Given

mass of truck(m)=1330 kg

height of hill(h)=16.1 m

work done by friction[tex](W_r)=-3.23\times 10^5 J[/tex]

Work done by engine[tex](W_e)=6.57\times 10^5 J[/tex]

and

change in Kinetic energy=

[tex]\Delta K E+\Delta U_{g}=W_r+W_e[/tex]

[tex]\Delta K E=-3.23\times 10^5+6.57\times 10^5-1330\times 9.8\times 16.1[/tex]

[tex]\Delta K E=(-3.23+6.57+2.09)\times 10^5[/tex]

[tex]\Delta K E=5.43\times 10^5 J[/tex]

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