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A piece of lead and a piece of zinc have a combined mass of 50.0 grams. The two pieces of metal are heated to 85.0 °C and then both are added to the same thermos bottle containing 100.0 grams of water at 22.2 °C. IF the final temperature of the water and metal is 23.9 °C, what was the mass of the lead?

Respuesta :

Answer:

m lead = 30.268g

Explanation:

q = m ΔT Cp

T final = 23.9C

q lead + q zinc = q water

m lead + m zinc = 50g

m lead x (85-23.9) x 0.130 + m zinc x (85-23.9) x 0.39 = 100 x (23.9 - 22.2) x 4.18

7.943 m lead + 23.829 m zinc = 710.6 ----- (m lead = 50g - m zinc)

m lead = 30.268g

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