Answer:
Answered
Explanation:
W = ∫ F dx = ∫ P dV = ∫ PA dx = PA* H = P∆V
∆V = W/P
= 1 kJ / 1200 kPa = 0.0 833 m3
Both cases the height is H = ∆V/A
IN case 1 ( sectional area = 0.01 m^2)
[tex]H_1 = \frac{0.000833}{0.01} = 0.0833[/tex]
in case 2 (sectional area = 0.03 m^2)
[tex]H_2 = \frac{0.000833}{0.03} = 0.0278[/tex]
