Answer:
1026.88 kilocalories are released by the combustion of 1.50 mol of glucose
Explanation:
First we have to calculate the amount in grams in 1.5 moles of glucose by using formula
Molecular mass of glucose is 180.156 g/mol
Mass in grams = Molarity x Molecular mass
=1.50 moles x 180.156 g/mol
= 270.23 g
Now we will calculate the amount of energy released
Energy released by 1 gram of glucose = 3.8 Kcal
Energy released by 270.23 gram of glucose = 3.8 x 270.23 Kcal
= 1026.88 Kcal
1026.88 kilocalories are released by the combustion of 1.50 mol of glucose
