Answer:
Range of f={-4,-3,0,5,12,21,32,...}
Step-by-step explanation:
We are given that a function
[tex]f(x)=x^2-4[/tex]
We have to find the range of f.
Substitute x=2 then we get
[tex]f(2)=(2)^2-4[/tex]
[tex]f(2)=4-4=0[/tex]
When we substitute x=0 then we get
[tex]f(0)=(0)^2-4=0-4=-4[/tex]
When we substitute x=1
[tex]f(1)=1-4=-3[/tex]
When x=3
[tex]f(3)=(3)^2-4=9-4=5[/tex]
Therefore, the range of f={-4,-3,0,5,12,21,32,...}
