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Last winter Armand had 5/6 of a row of stacked logs. At the end of the winter he had 8/15 of the same row left how much wood did he burn over the winter

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prinbunsongsikul

Answer:

[tex]\frac{3}{10}[/tex]

Step-by-step explanation:

First we have to make the fractions even so there denominator have to be equal. So 15 times 2 gets 30 and 6 times 5 gets 30 too. Now multiply the numerator by the corresponding number of 25/30 and 16/30. Subtract to get 9/30 now simplify to get 3/10.

Answer:

Armand burnt [tex]\frac{3}{10}[/tex] of wood over the winter.

Step-by-step explanation:

We know that Armand had in first place [tex]\frac{5}{6}[/tex].

Then, at the end of the winter, he had [tex]\frac{8}{15}[/tex].

To know how much wood he burnt, we just have to find the difference between these two quantities

[tex]\frac{5}{6}-\frac{8}{15}=\frac{75-48}{90}=\frac{27}{90}=\frac{3}{10}[/tex]

Therefore, Armand burnt [tex]\frac{3}{10}[/tex] of wood over the winter.

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