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You wish to prepare 50.00 mL of 0.0350 M NH3 from concentrated ammonia (15.28 M) by serial dilution using a 50 mL volumetric flasks, a 1.00 mL volumetric pipet, and a 10.00 mL graduated pipet. For the first dilution in the series, 1 mL of concentrated ammonia is added to a 50.00 volumetric flask and then filled to the line. The solution is mixed thoroughly, poured into a beaker, and then used to make the second solution in the series. What volume of the first solution should be used to make the second solution, 50.00 mL of 0.0350 M NH3 solution, using the glassware provided?

Respuesta :

Answer: The volume of ammonia required from first solution to make second solution is 5.72 mL

Explanation:

To calculate the molarity of the diluted solution, we use the equation:

[tex]M_1V_1=M_2V_2[/tex]        .......(1)

where,

[tex]M_1\text{ and }V_1[/tex] are the molarity and volume of the concentrated ammonia solution

[tex]M_2\text{ and }V_2[/tex] are the molarity and volume of diluted ammonia solution

We are given:

[tex]M_1=15.28M\\V_1=1mL\\M_2=?M\\V_2=50.00mL[/tex]

Putting values in equation 1, we get:

[tex]15.28\times 1=M_2\times 50.00\\\\M_2=0.3056M[/tex]

Now, calculating the volume of ammonia diluted from first dilution to make the required ammonia solution by using equation 1:

We are given:

[tex]M_1[/tex] = Molarity of ammonia solution from first dilution = 0.3056 M

[tex]V_1[/tex] = Volume of ammonia solution from first dilution = ?

[tex]M_2[/tex] = Molarity of ammonia to make second solution = 0.0350 M

[tex]V_2[/tex] = Volume of ammonia to make second solution = 50.00 mL

Putting values in equation 1, we get:

[tex]0.3056\times V_1=0.0350\times 50\\\\V_1=5.72mL[/tex]

Hence, the volume of ammonia required from first solution to make second solution is 5.72 mL

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