Answer:
initial speed = 12.96 m/s
Explanation:
Given data:
speed 3.95 m/s
height = 39.9 m
we know that time to reached the bottom is
[tex]H =\frac{1}{2} gt^2[/tex]
[tex]t = \sqrt{\frac{2H}{g}} [/tex]
[tex] = \sqrt{\frac{2\times 39.9}{9.8}}[/tex]
t = 2.855 sec
total time taken = 2.85 + 6.50 = 9.35 s
total distance at horizontal [tex]d = 3.95\times 9.35 = 36.95 m[/tex]
[tex]speed = \frac{d}{t} = \frac{36.95}{2.85} = 12.96 m/s[/tex]