Answer:
ABC is a line segment.
→∠A B D + ∠ C B D=180°→[By Linear pair Axiom]
→∠A B D+90°=180°
→∠A B D=90°
In ΔA B D and Δ C B D
AB=BC →[Given]
∠A B D = ∠ C B D→[Each being 90°]
BD is common.
→ΔA B D ~ Δ C B D→→[SAS]
AD=DC→→[C P CT]
BC=AB→[Given]
Segment AD must be congruent to DC.
Segment BC must be congruent to AB.
