Answer:
42
Step-by-step explanation:
Let x = the original number of bushes in garden A
Let x-9 = the original number of bushes in garden B
x-9-3=x-12 = bushes in garden B after transplanting 3
x+3 = bushes in garden A after transplanting 3
x+3=1.5(x-12)
x+3=1.5x-18
0.5x=21
x=42
There were 42 current bushes in garden A
Answer:
Garden A has 42 currant bushes before the transplant
Explanation:
Suppose garden A is x and garden B is y
Forming the linear equations
Garden A has 9 more currant bushes than garden B
Therefore
x=y+9 --------(1)
If 3 currant bushes are transplanted from Garden B to Garden A, then Garden A will have 1.5 times more currant bushes than Garden B.
When 3 currant bushes are transplanted then the new equation becomes
x=y+12--------(2)
Further after transplanting
x+3= 1.5y----------(3)
putting the value of y from equation 2 into equation 3
x+3 = 1.5(x-12)
x+3= 1.5x-18
x-1.5x=-18-3
-0.5x=-21
[tex]x=\frac{21\times 10}{5}[/tex]
x=42
Hence garden A has 42 currant bushes before the transplant
