Answer:
h = 36.4 cm
Explanation:
given,
spring constant = 2.5 x 10⁴ N/m
compressed distance = 11.2 cm = 0.112 m
mass of the child = 44 kg
maximum height = ?
by energy of conservation
[tex]K.E_i +P.E_i= K.E_f + P.E_f[/tex]
[tex]\dfrac{1}{2}kx^2 = mgh[/tex]
[tex]\dfrac{1}{2}\times 2.5 \times 10^4 \times 0.112^2 = 44\times 9.8 \times h[/tex]
[tex]\dfrac{1}{2}\times 2.5 \times 10^4 \times 0.112^2 = 44\times 9.8 \times h[/tex]
[tex]156.8 = 44 \times 9.8 \times h[/tex]
[tex]h = \dfrac{156.8}{44 \times 9.8}[/tex]
h = 0.364 m
h = 36.4 cm