It took the ball 6.94 seconds to make the trip
Explanation:
A bouncy ball is being thrown upwards with a velocity of 34 meters per
second and you caught the ball at the same height you released it
1. The initial velocity of the ball is 34 m/s upward
2. The acceleration of gravity is -9.8 m/s²
3. You caught the ball at the same height you released it
We need to find how long it takes the ball to make the trip
You caught the ball at the same height you released it, then
→ The displacement of the trip s = zero meter
→ The ball thrown upward with initial velocity u = 34 m/s
→ The acceleration of gravity g = -9.8 m/s²
→ s = u t + [tex]\frac{1}{2}[/tex] g t²
Substitute the values of u , g , s in the rules
→ 0 = 34 t + [tex]\frac{1}{2}[/tex] (-9.8) t²
→ 0 = 34 t - 4.9 t²
Multiply both sides by -1
→ 4.9 t² - 34 t = 0
Take t as common factor
→ t(4.9 t - 34) = 0
Equate each factor by 0
→ t = 0 ⇒ initial position
→ 4.9 t - 34 = 0
Add 34 to both sides
→ 4.9 t = 34
Divide both sides by 4.9
→ t = 6.94 seconds ⇒ final position
It took the ball 6.94 seconds to make the trip
Learn more:
You can learn more about free fall in https://brainly.com/question/5531630
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