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You have two resistors with the same cross sectional area and resistivity. Resistor A has length L1 and resistor B has length L2. Assume L2 > L1. If the resistors are connected in series with a battery, which resistor has the most power delivered to it? Explain. b: If they are connected in parallel with a battery, which resistor has the most power delivered to it? Explain.

Respuesta :

Answer:

Explanation:

Given

Resistor A has length [tex]L_1[/tex]

and Resistor B has Length [tex]L_2[/tex]

and Resistance is given by

[tex]R=\frac{\rho L}{A}[/tex]

Considering [tex]\rho [/tex]and A to be constant thus

[tex]R_2>R_1[/tex] because [tex]L_2>L_1[/tex]

(a)When they are connected in series

As the current in series is same and power is [tex]i^2R[/tex]

therefore [tex]P_2>P_1[/tex] as R is greater for second resistor

(b)if they are connected in Parallel

In Parallel connection Voltage is same

[tex]P=\frac{V^2}{R}[/tex]

resistance of 2 is greater than 1 thus Power delivered by 1 is greater than 2

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