Answer:
Step-by-step explanation:
Let w represent the width of the area. Then 2w+5 represents the length. The perimeter is twice the sum of length and width:
P = 2(L+W)
510 = 2(2w+5 +w) . . substitute given values
255 = 3w +5 . . . . . . divide by 2
250 = 3w . . . . . . . . . subtract 5
83 1/3 = w . . . . . . . . .divide by 3; the width of the area
2w+5 = 171 2/3 . . . . the length of the area
The fenced area is 83 1/3 ft wide and 171 2/3 ft long.