contestada

A 60 W lightbulb is on for 24 hours. A stereo with a power of 150 W is on for 2
hours. Which statement correctly compares the energy used by these
devices?
O
A. They use the same amount of energy.
O
B. The lightbulb uses 4,104,000 J more than the stereo.
O
c. The lightbulb uses 2,080,000 J less than the stereo
O
D. The lightbulb uses 5,184,000 J more than the stereo.
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Respuesta :

onyebuchinnaji

The correct statement is, the lightbulb uses 4,104,000 J more than the stereo.

Energy of consumed by the light bulb

The energy consumed by the light bulb for the given period of time is determined from the product of power and time of power dissipation.

E = pt

E = (60) x (24 x 3600 s)

E = 5,184,000 J

Energy of consumed by the stereo

The energy consumed by the stereo for the given period of time is calculated as follows;

E = Pt

E = (150) x (2 x 3600)

E = 1,080,000 J

Difference between the two energies

ΔE = 5,184,000 J - 1,080,000 J

ΔE = 4,104,000 J

Thus, we can conclude that, the lightbulb uses 4,104,000 J more than the stereo.

Learn more about power and energy here: https://brainly.com/question/13387946

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