Answer:
the object will travel 0.66 meters before to stop.
Explanation:
Using the energy conservation theorem:
[tex]E_i+K_i+W_f=K_f+U_f[/tex]
The work done by the friction force is given by:
[tex]W_f=F_f*d\\W_f=\µ*m*g*d\\W_f=0.35*4*9.81*d\\W_f=13.7d[J][/tex]
so:
[tex]\frac{1}{2}1800*(10*10^{-2})+0-13.7d=0+0\\d=0.66m[/tex]