Answer:
[tex]\mathbf{a2b}[/tex]
Step-by-step explanation:
We can simplify it twice.
1) Simplify at first by the factor outside the parentheses, namely 13. So dividing by 13.
[tex](a6b-3)13\\\\\frac{(a6b-3)13}{13} \Rightarrow (a6b-3)[/tex]
2) Since 6 and -3 are have as their GCD the number 3 then we can divide them both by 3.
[tex]\frac{(a6b)}{3}-\frac{3}{3}\Rightarrow (a2b)-1\Rightarrow\:a2b-1\Rightarrow a2b=1[/tex]
3) As the question just asks us the left side of the equation before the equal sign. We can rewrite a2b -1 as a2b=1 then the answer
[tex]\mathbf{a2b}[/tex]
