Answer:
+19.5 m/s
Explanation:
In the reference frame of the stationary observer, the bus is moving east at 18 m/s, so its velocity is:
v = +18 m/s
Where we have taken east as positive direction.
In the reference frame of the bus, the man is moving 1.5 m/s also east, so its velocity is
[tex]v_m' = +1.5 m/s[/tex]
Therefore, the velocity of the man in the reference frame of the stationary observer will be:
[tex]v_m = v + v_m' = +18 + 1.5 = +19.5 m/s[/tex]
