Answer:
The resistance of alight bulb is 240 ohms.
Explanation:
Given that,
Potential difference of a light bulb, V = 120 V
Current produced in the light bulb, I = 0.5 A
We need to find the resistance of the light bulb. It can be calculated using Ohm's law. It is given by :
V = IR
[tex]R=\dfrac{V}{I}[/tex]
[tex]R=\dfrac{120\ V}{0.5\ A}[/tex]
R = 240 ohms
So, the resistance of alight bulb is 240 ohms. Hence, this is the required solution.
