Respuesta :
Answer:
3/π Hz
Step-by-step explanation:
Recall that for a cos function in the form
y = A cos Bx
period = 2π / B
frequency = 1/period = B/2π
Given y = -5 cos 6x
A = -5 and B = 6
frequency,
= B / 2π
= 6 / 2π
= 3/π
Answer:
3/π Hz
Step-by-step explanation:
Recall that for a cos function in the form
y = A cos Bx
period = 2π / B
frequency = 1/period = B/2π
Given y = -5 cos 6x
A = -5 and B = 6
frequency,
= B / 2π
= 6 / 2π
= 3/π