Answer:
[tex]3\sqrt{6}[/tex] and [tex]-3\sqrt{6}[/tex]
Step-by-step explanation:
We will take numbers to one side and variables to one side eliminate the "Square" with "Square Root" and solve for the variable x. The process is shown below:
[tex]3x^2-10=152\\3x^2=152+10\\3x^2=162\\x^2=\frac{162}{3}\\x^2=54\\x=\sqrt{54}[/tex]
Now, we need to reduce the radical by using the rule shown below:
[tex]\sqrt{x*y}=\sqrt{x} \sqrt{y}[/tex]
Now,
[tex]\sqrt{54}=\sqrt{6*9} =\sqrt{6} \sqrt{9} =3\sqrt{6}[/tex]
The correct answer is [tex]3\sqrt{6}[/tex] and [tex]-3\sqrt{6}[/tex]
Note: squaring positive and negative makes the same answer
