A driver traveling at 100 km/h notices the speed limit changes to 50 km/h to enter town. The driver takes 0.9 s to slow down to 50 km/h with constant acceleration. We want to know how many meters the driver travels while slowing down.

Respuesta :

Answer:

18.72 m

Explanation:

Given initial speed of the vehicle(u) is 100 km/hr.=100*(5/18)m/sec=27.77m/sec

The final speed of the vehicle (v) is 50 km/h.=50*(5/18)m/sec=13.88m/sec

time taken(t)=0.9s

we know that v=u+at

13.88=27.77+a(0.9)

a= - 15.43m/[tex]sec^{2}[/tex]

Also we know that [tex]v^{2} -u^{2} =2as[/tex]

[tex]13.88^{2} -27.77^{2} =2*(-15.43)*(s)[/tex]

[tex]577.96=30.86*s[/tex]

s=18.72m

Therefore the distance travelled is 18.72 m

Answer:x= (v+v0/2) t

Explanation:

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