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An analysis indicated that the mercury (Hg) concentration of a stream was 0.68 parts per billion (ppb) by weight. What quantity of mercury in grams was present in 15.0 L of the water, the density of which is 0.998 g/ml?

Respuesta :

cristisp93

1.5 × 10⁻⁵ g of Hg

Explanation:

1 ppb = 1 gram in 10⁹ grams

So 0.68 ppb of mercury (Hg) are meaning that we have 0.68 g of Hg in 0.68 × 10⁹ grams of steam.

Now to calculate the mass of steam we use the following formula:

density = mass / volume

mass of steam = density × volume

mass of steam =  0.998 (g/ml) × 15000 mL

mass of steam = 14970 g

Now we devise the following reasoning:

if we have       0.68 g of Hg in 0.68 × 10⁹ g of steam

then we have  X  of Hg in 14970 g of steam

X = (0.68 × 14970) / 0.68 × 10⁹ = 14970 × 10⁻⁹ = 1.4970 × 10⁻⁵ = 1.5 × 10⁻⁵ g of Hg

Learn more about:

parts per billion (ppb)

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