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A cruise ship with a mass of 1.63 ✕ 107 kg strikes a pier at a speed of 0.772 as. It comes to rest after traveling 4.69 m, damaging the ship, the pier, and the tugboat captain's finances. Calculate the average force (in N) exerted on the pier using the concept of impulse. (Hint: First calculate the time it took to bring the ship to rest, assuming a constant force. Indicate the direction with the sign of your answer.)

Respuesta :

Answer:

[tex]F = 1.035 \times 10^6 N[/tex]

Explanation:

As we know by work energy theorem that work done by all forces must be equal to the change in kinetic energy of the system

So here we will have

[tex]W = \frac{1}{2}mv^2[/tex]

[tex]F. d = \frac{1}{2}mv^2[/tex]

so we will have

[tex]F = \frac{mv^2}{2d}[/tex]

now we have

[tex]m = 1.63 \times 10^7 kg[/tex]

[tex]v = 0.772 m/s[/tex]

[tex]d = 4.69 m[/tex]

now we have

[tex]F = \frac{(1.63 \times 10^7)0.772^2}{2(4.69)}[/tex]

[tex]F = 1.035 \times 10^6 N[/tex]