Answer:
B= magnetic field strength
Explanation:
use formula E = Blv
l=length
v=speed
this works if field &wire carrying current is perpendicular only
make sure you get your units right
Answer:
Magnetic field strength, [tex]B=6\ N/A-m[/tex]
Explanation:
Given that,
Length of the wire, l = 0.36 m
Speed with which the wire moves in a magnetic field, v = 0.21 m/s
The induced emf produced in the wire is 0.45 volts, [tex]\epsilon=0.45\ V[/tex]
It is a case of motional emf. When a wire moves in a magnetic field with velocity v, an emf is induced in the wire. It is given by :
[tex]\epsilon=Blv[/tex]
B is the magnetic field strength
[tex]B=\dfrac{\epsilon}{lv}[/tex]
[tex]B=\dfrac{0.45\ V}{0.36\ m\times 0.21\ m/s}[/tex]
[tex]B=5.95\ N/A-m[/tex]
or
[tex]B=6\ N/A-m[/tex]
So, the magnetic field strength is 6 N/A. Hence, this is the required solution.
