briannapham
contestada

Calculate the missing variables below using Charles's law

V1 = 3.17 L, T1 = 408 K
V2 = ? , T2 = 277 K

a. 2.15 L
b. 4.67 L
c. 0.214 L
d. No right answer.

Respuesta :

joseaaronlara

Answer:

The answer to your question is:  letter a

Explanation:

Data

V1 = 3.17 l

T1 = 408 K

V2 = ?

T2 = 277 K

Formula

Charles' law

                          [tex]\frac{V1}{T1} = \frac{V2}{T2}[/tex]

                          [tex]V2 = \frac{V1T2}{T1}[/tex]

                          [tex]V2 = \frac{(277)(3.17)}{408}[/tex]

                                 V2 = 2.15 L

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